Are you looking for the PDF Math Notes 11 Class Chapter 14 ” Solutions of Trigonometric Equation” online that you can view online in PDF format or direct download?
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These FSc Math Notes 11 Class Chapter 14 ”Solutions of Trigonometric Equation” notes are in accordance with the syllabus and paper pattern of Punjab Text Book Board Lahore. However, These notes are very useful for the students from various boards including the Sargodha Board, Lahore Board, Sahiwal Board, Multan Board, Kashmir Board, Rawalpindi Board, Gujranwala Board, and DG Khan Board.
To view online or download Math Notes For Class Chapter 14 in PDF Format, click the button given below. Additionally, Don’t forget to share these notes with your friend, class fellows, and teachers.
Math Notes 11 Class Chapter 14 Download PDF Links
Preview Math Notes 11 Class Chapter 14
Math Notes 11 Class Chapter 14
You can easily view or download these notes ease. In addition, if you want to view math notes from class 11 Chapter 14 Solutions of Trigonometric Equation, please ensure that you have a PDF reader installed on your computer. These notes cover the following topics:
 Introduction
 The Solution of General Trigonometric Equations
FSc PDF Math Notes 11 Class Chapter 12 contains only One exercise. We have provided this solution above These are:
Some important formulas

sin−1A+sin−1B=sin−1(A√1−B2+B√1−A2)${\mathrm{sin}}^{1}\ufffd+{\mathrm{sin}}^{1}\ufffd={\mathrm{sin}}^{1}\left(\ufffd\sqrt{1{\ufffd}^{2}}+\ufffd\sqrt{1{\ufffd}^{2}}\right)$

sin−1A−sin−1B=sin−1(A√1−B2−B√1−A2)${\mathrm{sin}}^{1}\ufffd{\mathrm{sin}}^{1}\ufffd={\mathrm{sin}}^{1}\left(\ufffd\sqrt{1{\ufffd}^{2}}\ufffd\sqrt{1{\ufffd}^{2}}\right)$

cos−1A+cos−1B=cos−1(AB−√(1−A2)(1−B2))${\mathrm{cos}}^{1}\ufffd+{\mathrm{cos}}^{1}\ufffd={\mathrm{cos}}^{1}\left(\ufffd\ufffd\sqrt{\left(1{\ufffd}^{2}\right)\left(1{\ufffd}^{2}\right)}\right)$

cos−1A−cos−1B=cos−1(AB+√(1−A2)(1−B2))${\mathrm{cos}}^{1}\ufffd{\mathrm{cos}}^{1}\ufffd={\mathrm{cos}}^{1}\left(\ufffd\ufffd+\sqrt{\left(1{\ufffd}^{2}\right)\left(1{\ufffd}^{2}\right)}\right)$

tan−1A+tan−1B=tan−1A+B1−AB${\mathrm{tan}}^{1}\ufffd+{\mathrm{tan}}^{1}\ufffd={\mathrm{tan}}^{1}\frac{\ufffd+\ufffd}{1\ufffd\ufffd}$

tan−1A−tan−1B=tan−1A−B1+AB
Definition Math Notes 11 Class
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MCQs Math Notes 11 Class
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Chapterwise MCQs Math Notes 11 Class
You may also be interested in the following 1styear notes for all subjects. Moreover To access and download these notes, simply click on the links given provided below.
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