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These FSc Math Notes 11 Class Chapter 13 ”Inverse Trigonometric Functions” notes are in accordance with the syllabus and paper pattern of Punjab Text Book Board Lahore. However, These notes are very useful for the students from various boards including the Sargodha Board, Lahore Board, Sahiwal Board, Multan Board, Kashmir Board, Rawalpindi Board, Gujranwala Board, and DG Khan Board.
To view online or download Math Notes For Class Chapter 13 in PDF Format, click the button given below. Additionally, Don’t forget to share these notes with your friend, class fellows, and teachers.
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Preview Math Notes 11 Class Chapter 13
Math Notes 11 Class Chapter 13
You can easily view or download these notes ease. In addition, if you want to view math notes from class 11 Chapter 13 Inverse Trigonometric Functions, please ensure that you have a PDF reader installed on your computer. These notes cover the following topics:
 Introduction
 The Inverse Sine Function
 The Inverse Cosine Function
 Inverse Tangent Function
 Inverse Cotangent, Scant, and Cosecant Functions
 Domains and Ranges of Principal Trigonometric Function and Inverse Functions
 Addition and Subtraction Formulas
FSc PDF Math Notes 11 Class Chapter 12 contains only Two exercises. We have provided this solution above These are:
Some important formulas

sin−1A+sin−1B=sin−1(A√1−B2+B√1−A2)${\mathrm{sin}}^{1}\ufffd+{\mathrm{sin}}^{1}\ufffd={\mathrm{sin}}^{1}\left(\ufffd\sqrt{1{\ufffd}^{2}}+\ufffd\sqrt{1{\ufffd}^{2}}\right)$

sin−1A−sin−1B=sin−1(A√1−B2−B√1−A2)${\mathrm{sin}}^{1}\ufffd{\mathrm{sin}}^{1}\ufffd={\mathrm{sin}}^{1}\left(\ufffd\sqrt{1{\ufffd}^{2}}\ufffd\sqrt{1{\ufffd}^{2}}\right)$

cos−1A+cos−1B=cos−1(AB−√(1−A2)(1−B2))${\mathrm{cos}}^{1}\ufffd+{\mathrm{cos}}^{1}\ufffd={\mathrm{cos}}^{1}\left(\ufffd\ufffd\sqrt{\left(1{\ufffd}^{2}\right)\left(1{\ufffd}^{2}\right)}\right)$

cos−1A−cos−1B=cos−1(AB+√(1−A2)(1−B2))${\mathrm{cos}}^{1}\ufffd{\mathrm{cos}}^{1}\ufffd={\mathrm{cos}}^{1}\left(\ufffd\ufffd+\sqrt{\left(1{\ufffd}^{2}\right)\left(1{\ufffd}^{2}\right)}\right)$

tan−1A+tan−1B=tan−1A+B1−AB$\mathrm{tan}}^{1}\ufffd+{\mathrm{tan}}^{1}\ufffd={\mathrm{tan}}^{1}\frac{\ufffd+\ufffd}{1\ufffd\ufffd$

tan−1A−tan−1B=tan−1A−B1+AB
Definition Math Notes 11 Class
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MCQs Math Notes 11 Class
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Chapterwise MCQs Math Notes 11 Class
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